SOLUTION: jim has one more than twice as many times than quarters. he has no other coins. if he has $3.25 in change, how many of each coin does jim have.
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Question 1168957: jim has one more than twice as many times than quarters. he has no other coins. if he has $3.25 in change, how many of each coin does jim have. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Jim has one more than twice as many dimes than quarters. he has no other coins.
d = 2q + 1
If he has $3.25 in change,
.10d + .25q = 3.25
Replace d with (2q+1)
.10(2q+1) + .25q = 3.25
.20q + .1 + .25q = 3.25
.45q = 3.25 - .10
.45q = 3.25 - .10
q = 3.15/.45
q = 7 quarters
then
d = 2(7) + 1
d = 15 dimes
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:
Check
.10(15) + .25(7) =
1.50 + 1.75 = 3.25
