q = number of quarters

d = number of dimes = q+7





25q + 10(q+7) = 350   (cents)

35q + 70 = 350

35q = 280

q = 280/35 = 8  --->  d = 15



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Ans: 8 quarters and 15 dimes

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Check:

 25(8) + 10(15) = 200 + 150 = 350  (= $3.50) (ok) 

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
 A man has a collection of dimes and quarters with a total of $3.50. If he has 7 more dimes than quarters, how many of each coins does he have?

======================

Set the "7 more dimes" aside.

Now it's pairs of 1Q & 1D worth $2.80

280/35 = 8 pairs.

+ 7 dimes ---> 8Q & 15D

 

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