SOLUTION: An ice cream parlor has one size of ice-cream cone for 7 cents and another for a cents. One afternoon when the smaller cones outsold the larger ones two to one, the sale totaled 6.

Question 1138532: An ice cream parlor has one size of ice-cream cone for 7 cents and another for a cents. One afternoon when the smaller cones outsold the larger ones two to one, the sale totaled 6.21 pesos. How many cones of each size were sold?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
x = the number of cones selling for 7 cents each.
y = the number of cones selling for a cents each.

one afternoon the smaller cones outsold the larger cones two to one for a total sale of 6.21 pesos.

.07 * x + a * y = 6.21

since y = 2x, the formula becomes:

.07 * x + a * 2x = 6.21.

factor out the x to get x * (.07 + 2a) = 6.21.

solve for x to get x = 6.21 / (.07 + 2a).

your answer depends on the value of a.

for example:

if the value of a = .01, then the formula becomes x = 6.21 / (.07 + 2 * .01) which becomes x= 6.21 / .09.

this results in x = 69.

since y = 2x, then y = 138.

.07 * x + .01 * y becomes .07 * 69 + .01 * 138 which is equal to 6.21.

if the value of a is anything else, like .05, then x = 6.21 / (x + 2a) becomes x = 6.21 / (x + .10) which becomes x = 6.21 / .17 which then becomes x = 36.52941176.

this makes y = 73.05882353.

.07x + .05y becomes .07 * 36.52941176 + .05 * 73.05882353 = 6.21.

thye formula works for any value of a, but you do need the value of a in order to find the value of x which you then double to find the value of y.

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