SOLUTION: jack has 4 more dimes than he has nickles if he has a total of 1.75 in his pocket how many nickels does he have?
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Question 1135405: jack has 4 more dimes than he has nickles if he has a total of 1.75 in his pocket how many nickels does he have?
Found 3 solutions by josgarithmetic, greenestamps, ikleyn:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
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Jack has 4 more dimes than he has nickles.
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if he has a total of $1.75 in his pocket,...
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..., how many nickels does he have?
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Nickels, n
Dimes, n+4
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Solve this and find .
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Informally....
(1) Count the "extra" 4 dimes and set them aside. The remaining coins are equal numbers of nickels and dimes, with a total value of $1.75-$0.40 = $1.35.
(2) Group the remaining coins in groups of one nickel and one dime each. The value of each group is $0.15.
(3) The number of groups worth $0.15 each needed to make the remaining $1.35 is 1.35/0.15 = 135/15 = 9; so there are 9 nickels and 9 dimes.
(4) Now bring back in those 4 dimes you set aside at the beginning, to find that the number of nickels in his pocket is 9 and the number of dimes is 13.
Answer by ikleyn(52802) (Show Source): You can put this solution on YOUR website!
.
If you want to learn on how to solve coin problems, look into the lesson on this subject that were written specially for you:
- Coin problems
- More Coin problems
- Solving coin problems without using equations
- Kevin and Randy Muise have a jar containing coins
- Typical coin problems from the archive
- Three methods for solving standard (typical) coin word problems
- More complicated coin problems
- Solving coin problems mentally by grouping without using equations
- Santa Claus helps solving coin problem
- Non-typical coin problems
- OVERVIEW of lessons on coin word problems
You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.
A convenient place to quickly observe these lessons from a "bird flight height" (a top view) is the last lesson in the list.
Read them and become an expert in solution of coin problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Coin problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
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