SOLUTION: Sandra has a total of one hundred fifty-one pennies, nickels and quarters. She has a total of $10.15. She has one more quarter than nickels and three times as many pennies as nicke

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Question 1127683: Sandra has a total of one hundred fifty-one pennies, nickels and quarters. She has a total of $10.15. She has one more quarter than nickels and three times as many pennies as nickels. How many of each coin does she have?
amchaconz@allumni.stanford.edu

Found 3 solutions by addingup, greenestamps, ikleyn:
Answer by addingup(3677)   (Show Source): You can put this solution on YOUR website!
either you don't know your own email address or you mis-spelled it or it's a phony. I don't care, here's your answer:
p + n + q = 151
and:
n+1 = q
3n = p
0.01p + 0.05n + 0.25q = 10.15
now substitute for pennies and quarters:
0.01(3n) + 0.05n + 0.25(n+1) = 10.15
0.03n + 0.05n + 0.25n + 0.25 = 10.15
0.33n = 9.90
n = 30 Sandra has 30 nickels
Quarters = n+1 = 30 + 1 = 31
Pennies = 3n = 30(3) = 90
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Check:
30(0.05) + 31(0.25) + 90(0.01) = 10.15 Correct
:
Happy learning!

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


The given information compares the numbers of both quarters and pennies to the number of nickels. That means it is probably easiest to set up the problem using the number of nickels as the variable.

Let x = number of nickels
Then x+1 = number of quarters ("...one more quarter than nickels")
And 3x = number of pennies ("three times as many pennies as nickels")

Write and solve the equation that says the total value of the nickels (5 cents each), quarters (25 cents each) and pennies (1 cent each) is $10.15 (1015 cents):






ANSWER: The coins she has are
x = 30 nickels
x+1 = 31 quarters
3x = 90 pennies

Answer by ikleyn(52794)   (Show Source): You can put this solution on YOUR website!
.
Sandra has a total of one hundred fifty-one pennies, nickels and quarters. She has a total of $10.15.
She has one more quarter than nickels and three times as many pennies as nickels. How many of each coin does she have?

amchaconz@allumni.stanford.edu
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


            It is clear, from the first glance, that the problem is over-defined: it contains more data than it is required for the solution.

            So, let be careful and will see what will happen in the course of the solution.


Let N be the number of nickels.


Then the number of quarters is (N+1)  and the number of pennies is 3N.


Your "coin" equation is  

    N + (N+1) + 3N = 151.


    5N + 1 = 151

    5N = 151-1 = 150  ====>  N = 150/5 = 30.


So far, we got  30 nickels, 31 quarter and 3*30 = 90 pennies.


CHECK.   30*5 + 31*25 + 90 = 10.15 cents.    !  Correct !


         The input data is consistent; the solution is correct.


Answer.  30 nickels, 31 quarter and 90 pennies.


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