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Sandra has a total of one hundred fifty-one pennies, nickels and quarters. She has a total of $10.15.
She has one more quarter than nickels and three times as many pennies as nickels. How many of each coin does she have?
amchaconz@allumni.stanford.edu
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It is clear, from the first glance, that the problem is over-defined: it contains more data than it is required for the solution.
So, let be careful and will see what will happen in the course of the solution.
Let N be the number of nickels.
Then the number of quarters is (N+1) and the number of pennies is 3N.
Your "coin" equation is
N + (N+1) + 3N = 151.
5N + 1 = 151
5N = 151-1 = 150 ====> N = 150/5 = 30.
So far, we got 30 nickels, 31 quarter and 3*30 = 90 pennies.
CHECK. 30*5 + 31*25 + 90 = 10.15 cents. ! Correct !
The input data is consistent; the solution is correct.
Answer. 30 nickels, 31 quarter and 90 pennies.