SOLUTION: Mr. Jones has $0.70 in dimes and nickels. The total number of coins is 2 more than 3 times the number of nickels. How many coins of each type does he have?

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Question 1126832: Mr. Jones has $0.70 in dimes and nickels. The total number of coins is 2 more than 3 times the number of nickels. How many coins of each type does he have?
Answer by ikleyn(52863)   (Show Source): You can put this solution on YOUR website!
.
The condition literally means that the number of dimes is TWO times the number of nickels PLUs 2:


    D = 2N + 2.


Then the money equations is


    5N + 10*(2N + 2) = 70   cents

    5N + 20N + 20 = 70

    25N = 70-20 = 50

    N = 50/25 = 2.


Answer.  2 nickels and  2*2+2 = 6 dimes.

You may check it on your own.

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On coin problems,  see the lessons
    - Coin problems
    - More Coin problems
    - Solving coin problems without using equations
    - Kevin and Randy Muise have a jar containing coins
    - Typical coin problems from the archive
    - Three methods for solving standard (typical) coin word problems
    - More complicated coin problems
    - Solving coin problems mentally by grouping without using equations
    - Santa Claus helps solving coin problem
    - OVERVIEW of lessons on coin word problems
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You will find there the lessons for all levels - from introductory to advanced,
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Read them and become an expert in solution of coin problems.

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The referred lessons are the part of this online textbook under the topic "Coin problems".


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Your problem has an original, fresh and unexpected formulation, and I like it - Thanks for posting it !


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