Let x be the number of P10 coins. Then the number of P1 coins is (x+4), and the number of P5 coins is (3x+2). The money equation then is (x+4) + 5*(3x+2) + 10x = 92 x + 15x + 10x + (4 + 10) = 92 26x = 92 - 14 = 78 x == 3. Answer. 3 P10 coins; (3+4) = 7 P1 coins; and 3x+2 = 3*3+2 = 11 P5 coins. Check. 3*10 + 7*1 + 11*5 = 92. ! Correct !