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A boy has 34 coins consisting of nickels and dimes. If the value of the coins is $2.20 .
How many nickels does the boy have ?
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Let's make first trial prediction by assuming for a minute that all 34 coins are nickels - then the total would be 5*34 = 170 cents,
making the shortage of 220 - 170 = 50 cents.
Hence, we should replace = 10 nickels by dimes to compensate the difference
(diminishing the difference of 50 cents by 5 cents at any single replacement).
So, the answer is: the original collection has 10 dimes and 34-10 = 24 nickels.
Check. 24*5 + 10*10 = 220 cents. ! Correct !
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It is a very standard coin word problem.
On coin problems, see the lessons
- Coin problems
- More Coin problems
- Solving coin problems without using equations
- Kevin and Randy Muise have a jar containing coins
- Typical coin problems from the archive
- Three methods for solving standard (typical) coin word problems
- More complicated coin problems
- Solving coin problems mentally by grouping without using equations
- Santa Claus helps solving coin problem
- OVERVIEW of lessons on coin word problems
in this site.
You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.
Read them and become an expert in solution of coin problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Coin problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
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