In all, there are 6*6 = 36 different outcomes (pairs of the dice values). They all are equally probable. Of these 36, there are only 3 (three), where the sum is greater than 10. These 3 are (5,6), (6,5) and (6,6). For the rest of 36 - 3 = 33 pairs the sum is at most 10. So the answer to the problem question is= .