SOLUTION: You took $10 in quarters, dimes and nickels from a jar of spare change. If you have twice as many quarters as nickels and 10 more dimes than quarters, how many coins of each type d

Question 1116971: You took $10 in quarters, dimes and nickels from a jar of spare change. If you have twice as many quarters as nickels and 10 more dimes than quarters, how many coins of each type do you have?
Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!

-

-----quarters
-
-----nickels
-
------dimes

CHECK:

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

You took $10 in quarters, dimes and nickels from a jar of spare change. If you have twice as many quarters as nickels and 10 more dimes than quarters, how many coins of each type do you have?

Let number of nickels be N
Then number of quarters = 2N, and number of dimes = 2N + 10
We then get: .05N + .25(2N) + .1(2N + 10) = 10
.05N + .5N + .2N + 1 = 10
.75N = 9
N, or number of nickels =
You should be able to find the number of quarters and dimes!
Answer by ikleyn(52798)   (Show Source): You can put this solution on YOUR website!
.

            You can solve this problem mentally !

Put aside 10 dimes for a moment. Then the remaining 9 dollars coin collection you can separate into groups containing 2 quarters, 1 nickel and 2 dimes each. Each such a group is worth 2*25 + 5 + 2*10 = 75 cents. The number of such groups is 900 cents divided by 75 cents, i.e. 12. So the original collection has 12 nickels, 24 quarters and 24+10 = 34 dimes.

Solved.

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On coin problems, see the lessons
    - Coin problems
    - More Coin problems
    - Solving coin problems without using equations
    - Kevin and Randy Muise have a jar containing coins
    - Typical coin problems from the archive
    - Three methods for solving standard (typical) coin word problems
    - More complicated coin problems
    - Solving coin problems mentally by grouping without using equations
    - Santa Claus helps solving coin problem
    - OVERVIEW of lessons on coin word problems
in this site.

You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.

Read them and become an expert in solution of coin problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Coin problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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