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Sunita has a coin collection of dimes, quarters, and silver dollars.
The number of quarters is 5 less then three-fourths of the number of dimes.
q = (3/4)d - 5
The number of silver dollars is 7 more than five-eighths of the number of dimes.
s = (5/8)d+7
There are 116 coins in all.
s + q + d = 116
Substitute for "q" and "s" and solve for "d"::
(5/8)d+7 + (3/4)d - 5 + d = 116
(5/8)d + (6/8)d + d = 116 - 7 + 5
(19/8)d = 114
d = = 48
Then q = (3/4)d - 5 = (3/4)*48 - 5 = 36-5 = 31.
s = (5/8)d+7 = (5/8)*48 + 7 = 30 + 7 = 37.
Answer. 48 dimes, 31 quarters and 37 silver dollars.
Solved.