SOLUTION: You have a jar containing 55 coins, consisting entirely of nickels and quarters, worth a total of $7.15. How many quarters are in the jar?

Question 1100752: You have a jar containing 55 coins, consisting entirely of nickels and quarters, worth a total of $7.15. How many quarters are in the jar?
Found 2 solutions by Fombitz, ikleyn:
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
1.
and

2.
Subtract 1 from 2,

Solve for Q then use either equation to solve for N.

Answer by ikleyn(52800)   (Show Source): You can put this solution on YOUR website!
.
You have a jar containing 55 coins, consisting entirely of nickels and quarters, worth a total of $7.15. How many quarters are in the jar?
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Let N be the number of nickels. Then the number of quarters is (55-N). The nickels contribute 5N cents to the total. The quarters contribute 25*(55-N) cents to the total. Thus the total is 5N + 25*(55-N) cents. According to he condition, it is 715 cents, so you have this "money" equation 5N + 25*(55-N) = 715. It is your basic equations. As soon as you got this equation and understood it, the setup part is completed. To solve the equation, simplify it step by step 5N + 1375 - 25N = 715 ====> -20N = 715 - 1375 = -660 ====> N = = 33. Answer. 33 nickels and 55-33 = 22 quarters. Check. 33*5 + 22*25 = 715 cents. ! Correct !

Solved.

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There is entire bunch of lessons on coin problems
    - Coin problems
    - More Coin problems
    - Solving coin problems without using equations
    - Kevin and Randy Muise have a jar containing coins
    - Typical coin problems from the archive
    - Three methods for solving standard (typical) coin word problems
    - More complicated coin problems
    - Solving coin problems mentally by grouping without using equations
    - Santa Claus helps solving coin problem
    - OVERVIEW of lessons on coin word problems
in this site.

You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.

Read them and become an expert in solution of coin problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Coin problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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