SOLUTION: "A collection of dimes and quarters is worth $9.55. If the quarters were dimes and the dimes were quaarters, the total value would be $7.60. Find the number of each coin."

Question 1099884: "A collection of dimes and quarters is worth $9.55. If the quarters were dimes and the dimes were quaarters, the total value would be $7.60. Find the number of each coin."
Found 5 solutions by josgarithmetic, MathTherapy, richwmiller, ikleyn, Alan3354:
Answer by josgarithmetic(39630)   (Show Source): You can put this solution on YOUR website!

Elimination Method may be best. (Or maybe, note that 191+152=343 and is divisible by 7).
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Answer by MathTherapy(10557)   (Show Source): You can put this solution on YOUR website!
"A collection of dimes and quarters is worth $9.55. If the quarters were dimes and the dimes were quaarters, the total value would be $7.60. Find the number of each coin."

Correct answer:
What is this UGLY TROLL'S problem? If I only give answers why don't you STOP getting on people NERVES and START showing them how to solve problems.
You've been on here doing nothing but making fun of people and they HATE YOU! Get off my back! You have been ANNOYING
and POKING fun at people for a long time. You need to see a psychiatrist because you're SICK! Some people on here have stated how they
wish they COULD meet you face-to-face to show you what ANNOYANCE is all about.
YOU MUST be JOSARITH's BOYFRIEND.
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
IGNORE everything this supposed tutor MathTherapy puts out there!
I have no idea why he chooses to come on here and just give ANSWERS with no work. Is that tutoring?
DAY AFTER DAY, AFTER DAY, AFTER DAY. I wonder when he'll stop, or if he'll ever stop!
I do not appreciate MathTherapy in the least. He offers nothing positive to this website. He is a proud and arrogant person who offers no understanding of tutoring nor teaching. I am not impressed that he gets an answer correct now and then.
His arrogant sometimes CORRECT answers with no work serve no useful purpose other than boosting his already bloated ego.
If you are going to insult someone at least get the name right.
You are a useless troll.
I am not here for a popularity contest. I take the website rules seriously.
The whiners don't want to follow the few rules we have here.
From Igor's (the owner and webmaster) own mouth
"It is an absolute REQUIREMENT that you MUST SHOW ALL WORK. Showing work is the best way to demonstrate your competence. Solutions without sufficient work shown are worthless.
Add your answer only if you feel you have something non trivial to add."

Answer by ikleyn(52905)   (Show Source): You can put this solution on YOUR website!
.
Dear tutor @richwmiller !

Besides providing his own solutions, tutor @MathTherapy performs everyday checking work for ALL of us, the tutors.

His contribution is evident, important and invaluable.

Therefore, I ask you immediately to erase your post and bring your apologies to @MathTherapy.

It would be right action from your side.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
We all make mistakes, some more than others.
Some are rude about it, most are not.
We'll all be dead eventually.
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