SOLUTION: Justin has $4.75 in quarters, dimes, and nickels. If he has a total of 27 coins and he has twice as many dimes as nickels, how many of each coin does he have?

Question 1095529: Justin has $4.75 in quarters, dimes, and nickels. If he has a total of 27 coins and he has twice as many dimes as nickels, how many of each coin does he have?
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!
he has twice as many dimes as nickels,


Let N = number of nickels
Then 2N = the number of dimes.

he has a total of 27 coins

Number of quarters = 27 - N - 2N Number of quarters = 27 - 3N

Justin has $4.75 in quarters, dimes, and nickels

0.25N + 0.10(2N) + 0.05(27-3N) = 4.75 Move the decimals two places right in each term: 25N + 10(2N) + 5(27-3N) = 475 Simplify and solve that for N, the number of nickels, then substitute what you get for N in: 2N = the number of dimes 27 - 3N = the number of quarters Edwin

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