SOLUTION: A person has four times as many nickels as dimes. If the total face value of these coins is $3.90, how many of each type of coin does this person have?

Question 1092700: A person has four times as many nickels as dimes. If the total face value of these coins is $3.90, how many of each type of coin does this person have?

Answer by ikleyn(52797) (Show Source): You can put this solution on YOUR website!
.

To solve this problem, group (MENTALLY) all the coins in sets containing 4 nickel and one dime each.


Each set (group) of coins then is worth  4*5+10 = 30 cents.


Hence, the number of such groups is   = 13.


From this point, can you complete the solution on your own ?

See the lesson
- Solving coin problems mentally by grouping without using equations
in this site.

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