SOLUTION: Bubba has 20 American coins, all quarters (25 cent coins) and dimes (10 cent coins). If the total value of his money is $ 3.05, how many of each type of coin does he have?

Question 1090276: Bubba has 20 American coins, all quarters (25 cent coins) and dimes (10 cent coins). If the total value of his money is $ 3.05, how many of each type of coin does he have?

Answer by ikleyn(52803) (Show Source): You can put this solution on YOUR website!
.

Let Q be the number of quarters.

Then the number of dimes is (20-Q), according to the condition.


The quarters contribute 25Q cents to the total.

The dimes contribute 10*(20-Q) cents to the total.


Your "value" equation is

25Q + 10*(20-Q) = 305   cents.


Simplify and solve for Q:

25Q + 200 - 10Q = 305  ====>  15Q = 305 - 200 = 105  ====>  Q =  = 7.


Answer.  7 quarters and  (20-7) = 13 dimes.

Check.   7*25 + 13*10 = 175 + 130 = 305 cents.   ! Correct !

Solved.

There is entire bunch of lessons on coin problems
    - Coin problems
    - More Coin problems
    - Solving coin problems without using equations
    - Kevin and Randy Muise have a jar containing coins
    - Typical coin problems from the archive
    - More complicated coin problems
    - Solving coin problems mentally by grouping without using equations
    - Santa Claus helps solving coin problem
    - OVERVIEW of lessons on coin word problems
in this site.

You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.

Read them and become an expert in solution of coin problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Coin problems".

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