SOLUTION: If roger has 43 coins consisting of only dimes and quarters and in total he has 6.55$ How many does he have of each coin

Question 1082710: If roger has 43 coins consisting of only dimes and quarters and in total he has 6.55$ How many does he have of each coin
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
If roger has 43 coins consisting of only dimes and quarters
d + q = 43
d = 43 - q; use this form for substitution
and in total he has 6.55$
.10d + .25q = 6.55
Replace d with (43-q)
.10(43 -q) + .25q = 6.55
4.3 - .10q + .25q = 6.55
.15q = 6.55 - 4.30
.15q = 2.25
q = 2.25/.15
q = 15 quarters
How many does he have of each coin
I'll let you find the no. of dimes, check the solutions using the 2nd equation
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