SOLUTION: jeff has $6.45 in quarters + dimes. he has 9 more quarters than dimes. how many coins of each type does he have?
Algebra.Com
Question 1076152: jeff has $6.45 in quarters + dimes. he has 9 more quarters than dimes. how many coins of each type does he have?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
Let d be the number of dimes jeff has. Then quarters are d+9. So:
10d+25(d+9)=645
35d=420
d=12
jeff has 12 dimes and 21 quarters. ☺☺☺☺
RELATED QUESTIONS
Sam has 2.05 in quarters and dimes. He has 4 more quarters than dimes. How many coins of... (answered by mananth)
Dj has $4.50 in dimes and quarters. he has 4 more quarters than dimes. How many coins of... (answered by oberobic)
jose has 6 more dimes than quarters. if his coins $1.65, how many coins of each type... (answered by xdragonfight)
Mark has 6 more quarters than dimes. he has $3.95 in all. how many coins of each type... (answered by Alan3354)
David has 12 coins, he has dimes and quarters. he has 6 more dimes than quarters,how many (answered by jorel1380)
leo has $4.00 IN DIMES AND QUARTERS. HE HAS 6 MORE DIMES THAN QUARTERS. HOW MANY QUARTERS (answered by oberobic)
Norman has a dollar consisting of nickels, dimes and quarters. He has 2 ore dimes tan... (answered by josgarithmetic,MathTherapy)
caleb has $10.95 in quarters, dimes and nickels. he has four more dimes than quarters. he (answered by Alan3354)
Tad has 6 more quarters than dimes. If he has $3.25 total, how many coins of each type... (answered by Paul)