SOLUTION: a coin purse contains $1812.50 composed of 25c, $1 and $5 coins. if the number of $1 is thirty times as many 0.25 cents and the $5 is two more than $1, how many of each coins are i

Question 1074868: a coin purse contains $1812.50 composed of 25c, $1 and $5 coins. if the number of $1 is thirty times as many 0.25 cents and the $5 is two more than $1, how many of each coins are in the purse?
Answer by ikleyn(52887) (Show Source): You can put this solution on YOUR website!
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a coin purse contains $1812.50 composed of 25c, $1 and $5 coins. if the number of $1 is thirty times as many 25 cents
and the $5 is two more than $1, how many of each coins are in the purse?
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Let x = the number of 25-cent coins.


Then your equation is

0.25x + 1*(30x) + 5*(30x+2) = 1812.50.


Multiply both sides by 100 to be more happy. You will get

25x + 3000x + 15000x + 1000 = 181250,   or

18025x = 180250  --->  x = 10.


Thus there are 10 25-cent coins.


Answer.  10 25-cent coins, 300 $1-coins and 302 $5-coins.

Check.   10*0.25 + 300 + 302*5 = 1812.50.

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