.
Let Q be the number of quarters.
Then the number of nickels is (38-Q).
Quarters contribute 25Q cents to the total.
Nickels contribute 5*(38-Q) cents to the total.
The "value" equation is
25Q + 5*(38-Q) = 510 cents.
25Q + 190 -5Q = 510,
20Q = 510 - 190 ---> 20Q = 320 ---> Q = = 16.
Answer. 16 quarters (= $4.00) and 38-16 = 22 nickels (= $1.10).
Solved.
There is entire bunch of lessons on coin problems
- Coin problems
- More Coin problems
- Solving coin problems without using equations
- Kevin and Randy Muise have a jar containing coins
- Typical coin problems from the archive
- More complicated coin problems
- Solving coin problems mentally by grouping without using equations
- Santa Claus helps solving coin problem
in this site.
You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.
Read them and become an expert in solution of coin problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Coin problems".