Question 1070015: there is $4.50 in a bag of change, we have nickels, dimes and quarters, if we have a total of 28 coins, how many of each do I have??? Found 3 solutions by josgarithmetic, yalmarg, MathTherapy:Answer by josgarithmetic(39800) (Show Source): You can put this solution on YOUR website! $4.50 could be made with 18 quarters, but you want 28 total coins.
One quarter, $0.25, can be split into 1 nickel and 2 dimes. Each such splitting will add 2 coins to the combination of coins.
17 q + 1 n + 2 d = 4.50, count of 20 coins;
16 q + 2 n + 4 d = 4.50, count of 22 coins;
Keep going like this and find:
13 q +5 n + 10 d = 4.50, 28 coins.
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COMBINATION:
13 quarters
5 nickels
10 dimes
---------------------- Answer by yalmarg(1) (Show Source): You can put this solution on YOUR website! I find out also:
5n+10d+25q=450
n+d+q=28
For d=62-4q and for n=3q-34
so we start solving for possible solutions,
q d n total coins
10 22 4 36
11 18 1 30
12 14 2 28
13 10 5 28
14 6 8 28
15 4 11 30
Three solutions.
This gives me more questions than answers...
Can someone please help me to determine which way to go or if there is any specific format or formula for this type of word problem??? Answer by MathTherapy(10810) (Show Source): You can put this solution on YOUR website! there is $4.50 in a bag of change, we have nickels, dimes and quarters, if we have a total of 28 coins, how many of each do I have???
Four (4) combinations:
Do you happen to see a PATTERN?