SOLUTION: A jar of 45 coins consists only of nickels, dimes, and quarters, with a face value of $5.90. The numbers of nickels and dimes together exceed the number of quarters by 19. How many

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Question 1069343: A jar of 45 coins consists only of nickels, dimes, and quarters, with a face value of $5.90. The numbers of nickels and dimes together exceed the number of quarters by 19. How many quarters are in the jar?
Answer by ikleyn(52847)   (Show Source): You can put this solution on YOUR website!
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A jar of 45 coins consists only of nickels, dimes, and quarters, with a face value of $5.90.
The numbers of nickels and dimes together exceed the number of quarters by 19. How many quarters are in the jar?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

N + D + Q = 45,    (1)
N + D - Q = 19.    (2)

Subtract eq(2) from eq(1) (both sides). You will get

2Q = 45 - 19 = 26   --->  Q =  = 13.

Answer. 13 quarters.

The info about "face value" is excessive, unnecessary and serves for only one goal: to confuse the reader.

It is not used in the solution.


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