SOLUTION: Jill had $3.50 in nickel and dimes. If she has 50 coins, how many of each type of coins does she have?
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Question 106920: Jill had $3.50 in nickel and dimes. If she has 50 coins, how many of each type of coins does she have?
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
N+D=50 OR N=50-D
.05(50-D)+.10D=3.50
2.5-.05D+.10D=3.50
.05D=3.50-2.50
.05D=1.00
D=1.00/.05
D=20 NUMBER OF DIMES.
50-20=30 NUMBER OF NICKLES.
PROOF
.05*30+.10*20=3.50
1.50+2.00=3.50
3.50=3.50
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