SOLUTION: Anna had $2.00. she has six more dimes than quarters. How many of each coin did she have?
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Question 1068355: Anna had $2.00. she has six more dimes than quarters. How many of each coin did she have?
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
d = q+6
0.10d+0.25q = 2
0.10(q+6)+0.25q = 2
0.10q+0.6+0.25q = 2
0.10q+0.25q = 2-0.6
0.35q = 1.40
q = 4 so she has 4 quarter and the problem says she has 6 more dimes than q:
4+6 = 10 she has 10 dimes
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Check:
4 × 0.25 = 1
10 × 0.10= 1
Total . . 2 Correct
:
John
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