SOLUTION: Newgy has twice as many nickels as dimes,and four times as many pennies as nickels. If she has a total of $2.80, how many of each coin does she have?

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Question 1063402: Newgy has twice as many nickels as dimes,and four times as many pennies as nickels. If she has a total of $2.80, how many of each coin does she have?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39625)   (Show Source): You can put this solution on YOUR website!
p pennies
n nickels
d dimes
-




d and p are in terms of n.

Substitution gives a single equation in just one unknown variable:




The other two follow easily.
Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!
Newgy has twice as many nickels as dimes,and four times as many pennies as nickels. If she has a total of $2.80, how many of each coin does she have?
Let number of dimes be D

Then number of nickels = 2D

Number of pennies = 4(2D), or 8D

We then get: .1D + .05(2D) + .01(8D) = 2.8

.1D + .1D + .08D = 2.8

.28D = 2.8

D, or number of dimes = 

Number of nickels: 

Number of pennies: 

It's as easy as that....nothing COMPLEX and/or CONFUSING! 

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