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angelina has a collection of nickels and dimes worth $4.75. If she has 70 dimes and nickels, how many of each does she have?
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Let "n" be the number of nickels in the collection.
Then the number of dimes is (70-n).
Nickels contribute 5n cents to the total.
Dimes contribute 10*(70-n) cents to the total.
The total is
5n + 10*(70-n) = 475 cents.
Simplify and solve for "n":
5n + 700 - 10n = 475,
-5n = 475 - 700,
-5n = -225,
n = = 45.
Answer. There are 45 nickels and 70-45 = 25 dimes in the collection.
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For coin problems and their detailed solutions see the lessons in this site:
- Coin problems
- More Coin problems
- Solving coin problems without using equations
- Kevin and Randy Muise have a jar containing coins
- Typical coin problems from the archive
- Solving coin problems mentally by grouping without using equations
- Santa Claus helps solving coin problem
Read them attentively and become an expert in this field.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Coin problems".