SOLUTION: When Jai emptied her piggy bank, there were nickels, dimes, and quarters. There were 2 times as many dimes as nickels, and 10 more quarters than nickels. If the total amount of mon

Question 1061226: When Jai emptied her piggy bank, there were nickels, dimes, and quarters. There were 2 times as many dimes as nickels, and 10 more quarters than nickels. If the total amount of money was 7.50, how many coins did she have?
Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
VARIABLES
n nickels
d dimes
q quarters

EQUATIONS FROM DESCRIPTION

SIMPLIFY OR IMPROVE THE SYSTEM

Actual form of each equation may be chosen differently, but system must still be equivalent.

SUGGESTION:
substitute for d in the last equation of that simplified system, and solve the resulting system in n and q.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
When Jai emptied her piggy bank, there were nickels, dimes, and quarters. There were 2 times as many dimes as nickels, and 10 more quarters than nickels. If the total amount of money was 7.50, how many coins did she have?

Let number of nickels be N
Then number of dimes = 2N
Number of quarters: N + 10
We then get the following VALUE equation: .05N + .1(2N) + .25(N + 10) = 7.5
.05N + .2N + .25N + 2.5 = 7.5
.5N = 7.5 - 2.5
.5N = 5
N, or number of nickels =
Number of dimes:
Number of quarters:
She had a total of:
It is that simple....nothing CONFUSING and COMPLEX!
Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.
The tutor "MathTherapy" proposed and implemented very reasonable methodolgy.

The way of "josgarithmetic" is the way to "nowhere". Do not take it seriously. Simply ignore it.

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