SOLUTION: Emma paid the $10.46 bill for her lunch with 242 coins consisting of pennies,nickels,and dimes. if the number of nickles plus the number of dimes was equal to the number of pennies
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Question 1060063: Emma paid the $10.46 bill for her lunch with 242 coins consisting of pennies,nickels,and dimes. if the number of nickles plus the number of dimes was equal to the number of pennies, then how many coins if each type did she use ?
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
p = number of pennies
n = number of nickels
d = number of dimes
p + n + d = 242
p + 5n + 10d = 1046
n + d = p
Write everything in terms of n and d:
2n + 2d = 242
6n + 11d = 1046
Use any method (graphing, substitution, elimination) to solve for n and d, but we will use elimination.
6n + 6d = 726
-6n - 11d = -1046
------------------------
-5d = -320
d = 64 ----> n = 57
There were 121 pennies, 57 nickels, and 64 dimes.
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