SOLUTION: Shari has 17 coins consisting of dimes and quarters worth $3.35. How many quarters and how many dimes does she have
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Question 1060028: Shari has 17 coins consisting of dimes and quarters worth $3.35. How many quarters and how many dimes does she have
Found 2 solutions by Alan3354, acw1213:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Shari has 17 coins consisting of dimes and quarters worth $3.35. How many quarters and how many dimes does she have
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d + q = 17
10d + 25q = 335
Answer by acw1213(28) (Show Source): You can put this solution on YOUR website!
Let "d" represent the amount of dimes Shari has.
Let "q" represent the amount of quarters Shari has.
The amount a dime and a quarter can be represented by decimals.
.10 = a dime
.25 = a quarter
Write a systems of equations and solve.
.10d + .25q = 3.35
d + q = 17
I'm going to solve this using the substitution method.
d + q = 17
subtract "q" from both sides
d = 17 - q
Substitute 17 - q for "d" in the first equation.
.10(17 - q) + .25q = 3.35
Distribute
1.7 - .10q + .25q = 3.35
Combine like terms
1.7 + 0.15q = 3.35
Solve for "q"
Subtract 1.7 on both sides
0.15q = 1.65
Divide by 0.15 on both sides
She has 11 quarters.
Plug in 11 for "q" in the second equation.
d + 11 = 17
Subtract 11 on both sides
d = 6
She has 11 quarters and 6 dimes.
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