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Jonathan finds 52 cents in his car consisting of pennies, nickels, and dimes. He finds 2 more nickels than dimes,
and three times as many pennies as nickels. How many of each coin does he find?
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For a moment, put aside 2 nickels and 6 pennies (mentally).
Then the remained coins worth is 52 - 2*5 - 6 = 36 cents.
Now you can group the rest of the coins in sets containing {1 nickel, 1 dime, 3 pennies} each.
Each set worth is 5 + 10 + 3 = 18 cents.
How many such sets are there among remained coins? = 2.
Now return back that coins you put aside at the beginning.
Answer. 2+2 = 4 nickels, 2 dimes and 3*2+6 = 12 pennies were there in the collection.
This method allows to solve the problem without using equations.
There is entire bunch of lessons on coin problems
- Coin problems
- More Coin problems
- Solving coin problems without using equations
- Kevin and Randy Muise have a jar containing coins
- Typical coin problems from the archive
- More complicated coin problems
- Solving coin problems mentally by grouping without using equations
- Santa Claus helps solving coin problem
- OVERVIEW of lessons on coin word problems
in this site.
Read them and become an expert in solution of coin problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Coin problems".