SOLUTION: A collection of coins consisting of dimes and quarters has a value of $2.55. If the number of dimes is 3 more than twice the number of quarters, how many of each type of coin are t

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Question 1057242: A collection of coins consisting of dimes and quarters has a value of $2.55. If the number of dimes is 3 more than twice the number of quarters, how many of each type of coin are there?
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52794)   (Show Source): You can put this solution on YOUR website!
.
A collection of coins consisting of dimes and quarters has a value of $2.55. If the number of dimes is 3 more
than twice the number of quarters, how many of each type of coin are there?
~~~~~~~~~~~~~~~~~~~~~~~~~~ 

From the condition, you have these two equations

10d + 25q = 255,   (1)
d = 2q + 3.        (2)

substitute expression (2) to the equation (1), replacing d. You will get

10(2q +3) + 25q = 255,   or

20q + 30 + 25q = 255,  or

45q = 255 - 30,

45q = 225.

q =  = 5

5 quarters and 2*5 + 3 = 13 dimes.

Sorry, it was MY mistake.


Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

A collection of coins consisting of dimes and quarters has a value of $2.55. If the number of dimes is 3 more than twice the number of quarters, how many of each type of coin are there?
 

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