SOLUTION: Devyn has 108 coins in nickels and quarters worth $12.60. Write and solve an equation to determine how many of each coin she has.

Question 1054602: Devyn has 108 coins in nickels and quarters worth $12.60. Write and solve an equation to determine how many of each coin she has.
Answer by ikleyn(53763) (Show Source): You can put this solution on YOUR website!
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Devyn has 108 coins in nickels and quarters worth $12.60. Write and solve an equation to determine how many of each coin she has.
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Let "n" be the number of nickels.
Then the number of quarters is (108-n).

Nickels contribute 5n cents into the total.
Quarters contribute 25*(108-n) cents into the total.

The "value" equation is 

5n + 25(108-n) = 1260.

Simplify and solve for n:

5n + 2700 - 25n = 1260,  or

-20n = 1260 - 2700,

-20n = -1440  --->  n =  = 72.

Answer. The number of nickels is 72.
        The number of quarters is 108-72 = 36.

There is entire bunch of the lessons on coin problems
    - Coin problems
    - More Coin problems
    - Solving coin problems without using equations
    - Kevin and Randy Muise have a jar containing coins
    - Typical coin problems from the archive
    - More complicated coin problems
in this site.

Read them and become an expert in solution of coin problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Coin problems".

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