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Sue has $3.25 in dimes and nickels. If she has 10 more dimes as nickels, how many of each coin does she have?
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Let me show you how to solve the problem mentally, without equations.
Take off 10 dimes from the collection (mentally ).
Then Sue has $2.25 in dimes and nickels, and the number of nickels is the same as dimes.
Combine the remaining coins in groups with one dime and one nickel in each group.
Each group worth 5 + 10 = 15 cents. Hence, there are 225/15 = 15 groups.
It means that there were 15 nickels in the collection originally.
So, your answer: there were 15 nickels and 25 dimes in Sue's collection.
See the lessons
- Coin problems
- More Coin problems
- Kevin and Randy Muise have a jar containing coins
- Typical coin problems from the archive
- More complicated coin problems
in this site to learn on how to solve coin problems using equations.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.