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41 coins nickels and dimes together adds up to 2.75 how many nickels are there 
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Let "n" be the number of nickels in the collection.
Then the number of dimes is (41-n).
Nickels contribute 5n       cents into the total.
Dimes   contribute 10(41-n) cents into the total.
The total is 5n + 10(41-n) cents.
From the other side. the total is 275 cents, according to the condition.
Hence,
5n + 10(41-n) = 275.
It is your equation to solve for "n". Simplify it:
5n + 410 - 10n = 275,
-5n = 275 - 410,
-5n = -135,
n =  = 27.
Answer.  The number of nickels in the collection is 27.
Check.   Then the number of dimes is 41-27 = 14.
         27*5 + 14*10 = 275.  OK, correct !
For many other similar solved problems on coins see the lessons
    - Coin problems
    - More Coin problems
    - Solving coin problems without using equations
    - Kevin and Randy Muise have a jar containing coins
    - Typical coin problems from the archive
in this site.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.