SOLUTION: mike has $.90 in dimes & nickles. if he has 6 more dimes than nickels, how many of each does he have
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Question 1044962: mike has $.90 in dimes & nickles. if he has 6 more dimes than nickels, how many of each does he have
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
d = n+6
0.1d+0.05n = 0.90 Substitute for d:
0.1(n+6)+0.05n = 0.90
0.1n+0.6+0.05n = 0.90
0.15n = 0.3
n = 2 He has 2 nickels and 0.9-2(0.05)=0.8; 0.8/0.1= 8 dimes
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