Let the number of dimes be x Let the number of quarters be y Value Value Type Number of of of of EACH ALL coin coins coin coins ------------------------------------------- dimes x $0.10 $0.10x quarters y $0.25 $0.25y ------------------------------------------- TOTALS 37 ----- $5.95 The first equation comes from the "Number of coins" column.x + y = 37 The second equation comes from the "Value of all coins" column. 0.10x + 0.25y = 5.95 Get rid of decimals by multiplying every term by 100: 10x + 25y = 595 So we have the system of equations: . We solve by substitution. Solve the first equation for y: x + y = 37 y = 37 - x Substitute (37 - x) for y in 10x + 25y = 595 10x + 25(37 - x) = 595 10x + 925 - 25x = 595 -15x + 925 = 595 -15x = -330 x = 22 = the number of dimes. Substitute in y = 37 - x y = 37 - (22) y = 15 quarters. Checking: 22 dimes is $2.20 and 15 quarters is $3.75 That's 37 coins. And indeed $2.20 + $3.75 = $5.95 Edwin