SOLUTION: If a jar contains 21 coins, all of which are either nickles or dimes . And the total value is $1.75 , how many coins of each are in the jar?

Question 1034000: If a jar contains 21 coins, all of which are either nickles or dimes . And the total value is $1.75 , how many coins of each are in the jar?
Found 3 solutions by stanbon, ikleyn, MathTherapy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
If a jar contains 21 coins, all of which are either nickles or dimes . And the total value is $1.75 , how many coins of each are in the jar?
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Quantity:: n + d = 21 coins
Value:::: 5n + 10d = 175
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Modify for elimination::
n + d = 21
n + 2d = 87.5
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Subtract and solve for "d":
d = 66.5
Note:: d must be a positive whole number.
Please check your post.
Cheers,
Stan H.
Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.
If a jar contains 21 coins, all of which are either nickles or dimes . And the total value is $1.75 , how many coins of each are in the jar?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-------
Quantity:: n + d = 21 coins
Value:::: 5n + 10d = 175
----------------------
Modify for elimination::
n + d = 21
n + 2d = 35
------------------------
Subtract and solve for "d":
d = 14.

Answer. 14 dimes and 7 nickels.

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

If a jar contains 21 coins, all of which are either nickles or dimes . And the total value is $1.75 , how many coins of each are in the jar?

Let number of nickels be N
Then number of dimes is: 21 - N
The following VALUE equation is then derived: .05N + .1(21 - N) = 1.75
.05N + 2.1 - .1N = 1.75
.05N - .1N = 1.75 - 2.1
- .05N = - .35
N, or number of nickels = =
Number of dimes = 21 - 7, or
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