Let the number of dimes be x Let the number of quarters be y Value Value Type Number of of of of EACH ALL coin coins coin coins ------------------------------------------- dimes x $0.10 $0.10x quarters y $0.25 $0.25y ------------------------------------------- TOTALS 41 ----- $6.80 The first equation comes from the "Number of coins" column.x + y = 41 The second equation comes from the last column. 0.10x + 0.25y = 6.80 Get rid of decimals by multiplying every term by 100: 10x + 25y = 680 So we have the system of equations: . We solve by substitution. Solve the first equation for y: x + y = 41 y = 41 - x Substitute (41 - x) for y in 10x + 25y = 680 10x + 25(41 - x) = 680 10x + 1025 - 25x = 680 -15x + 1025 = 680 -15x = -345 x = 23 = the number of dimes. Substitute in y = 41 - x y = 41 - (23 y = 18 quarters. Checking: 23 dimes is $2.30 and 18 quarters is $4.50 That's 41 coins. And indeed $2.30 + $4.50 = $6.8 Edwin