SOLUTION: Lauren had exactly $1 in change. She had only quarters,dimes,and nickels. If she had 12 coins did she have?

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Question 1026952: Lauren had exactly $1 in change. She had only quarters,dimes,and nickels. If she had 12 coins did she have?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
q, d, n, quarters dimes nickels;





You have really just two equations but three unknown variables. The most restrictive variable would be q for quarters. You know the quantity could only be from 1 to 3, so just try those different values and solve for d and n.
Answer by ikleyn(52795)   (Show Source): You can put this solution on YOUR website!
.
Lauren had exactly $1 in change. She had only quarters,dimes,and nickels. If she had 12 coins did she have?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

Answer:  2 quarters, 1 dime and 8 nickels.

Check:  1) 2 + 1 + 8 = 11;  2) 2*25 + 1*10 + 8*5 = 100.

The method:  Trial and error. Start with quarters.


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