SOLUTION: Kevin has $4.85 in nickels and dimes. If he has 34 fewer dimes than nickels, how many coins (nickels and dimes) does he have altogether?
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Question 1026020: Kevin has $4.85 in nickels and dimes. If he has 34 fewer dimes than nickels, how many coins (nickels and dimes) does he have altogether?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Kevin has $4.85 in nickels and dimes. If he has 34 fewer dimes than nickels, how many coins (nickels and dimes) does he have altogether?
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n = d + 34
5n + 10d = 485
etc
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another method:
Set the 34 more nickels aside.
--> pairs of 1n & 1d each worth 15 cents & a total of $3.15 ($4.85 - $1.70)
315/15 = 21 pairs
--> 21 dimes and 55 nickels
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