SOLUTION: Isabelle paid for her $1.75 with 87 coins. If all of the coins were nickels and pennies, then how many were there of each type?

Question 1023383: Isabelle paid for her $1.75 with 87 coins. If all of the coins were nickels and pennies, then how many were there of each type?
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the numbers of nickels and pennies, n and p.
Thus we can write
n + p = 87 and the value equation
5n + p = 175 (we work in cents)
Now subtract the equations and get
-4n = - 88
n = 22 nickels
which means
p = 65 pennies (they add to 87 coins)...
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