SOLUTION: 200 coins. Consisting of 1php and 25 centavos. If you add all the 1php and 25c the sum is 95php. How many coins of each kind are there?

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Question 1022702: 200 coins. Consisting of 1php and 25 centavos. If you add all the 1php and 25c the sum is 95php. How many coins of each kind are there?
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
I do not know your money system.  So I'm guessing.

Let the number of 1phps be x
Let the number of 25centavos be y


                      Value      Value
Type       Number       of         of
 of          of        EACH       ALL
coin        coins      coin      coins
-------------------------------------------
1phps        x      1php          1x php
25centavos   y      0.25php    0.25y php
-------------------------------------------
TOTALS       200      -----       95 php

 The first equation comes from the second column.

  

                 x + y = 200

 The second equation comes from the last column.
  

            1x + 0.25y = 95

Get rid of decimals by multiplying every term by 100:

          100x + 25y = 9500

 So we have the system of equations:
           .

We solve by substitution.  Solve the first equation for y:

           x + y = 200
               y = 200 - x

Substitute (200 - x) for y in 100x + 25y = 9500

   100x + 25(200 - x) = 9500
    100x + 5000 - 25x = 9500
           75x + 5000 = 9500
                  75x = 4500
                    x = 60 = the number of 1phps.

Substitute in y = 200 - x
              y = 200 - (60)
              y = 140 25centavos.


Edwin


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