SOLUTION: A man has $0.70 in dimes and nickels. He has 8 coins altogether. How many nickels does he have?
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Question 1017023: A man has $0.70 in dimes and nickels. He has 8 coins altogether. How many nickels does he have?
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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N=nickels; D=dimes
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N+D=8
N=8-D
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$0.05N+$0.10D=$0.70
$0.05(8-D)+$0.10D=$0.70
$0.40-$0.05D+$0.10D=$0.70
$0.05D=$0.30
D=6 . There are 6 dimes.
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N=8-D=8-6=2
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ANSWER: There are 2 nickels.
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CHECK:
$0.05N+$0.10D=$0.70
$0.05(2)+$0.10(6)=$0.70
$0.10+$0.60=$0.70
$0.70=$0.70
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