SOLUTION: Brendan has $6.50, and it is made up of 10 cent and 59 cent coins. If he has 25 coins altogether, how many coins of each kind does he have?

Question 1015511: Brendan has $6.50, and it is made up of 10 cent and 59 cent coins. If he has 25 coins altogether, how many coins of each kind does he have?
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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There is no answer to this question as given.
If he has 10 cent coins and 50 cent coins (not 59 cent coins):
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T=number of 10 cent coins; F=number of fifty cent coins
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T+F=25
T=25-F . Use this to substitute for T later.
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$0.10T+$0.50F=$6.50 . Substitute for T.
$0.10(25-F)+$0.50F=$6.50
$2.50-$0.10F+$0.50F=$6.50
$0.40F=$4.00
F=10
ANSWER 1: He has ten fifty cent coins.
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T=25-F=25-10=15
ANSWER 2: He has fifteen 10 cent coins
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CHECK:
$0.10T+$0.50F=$6.50
$0.10(15)+$0.50(10)=$6.50
$1.50+$5.00-$6.50
$6.50=$6.50
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