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A jar contains only nickels and dimes and there is 200 coins in the jar. The value is 14 dollars. How many nickels and dimes are in the jar?
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Let n = # of nickels and d = # of dimes.
Then your equations are
n + d = 200, (1)
5n + 10d = 1400. (2)
To solve this system, express n via d from (1): n = 200 - d, and substitute it into (2). You will get
5*(200-d) + 10d = 1400.
Simplify it:
1000 - 5d + 10d = 1400,
5d = 1400 - 1000 = 400,
d = = 80.
Answer. 80 dimes and 200-80 = 120 nickels.