SOLUTION: John collects coins. He has 51 coins, consisting of dimes and nickles, that are worth $3.35. How many of each type of coin does he have?

Question 1014513: John collects coins. He has 51 coins, consisting of dimes and nickles, that are worth $3.35. How many of each type of coin does he have?
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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N=nickels; D=dimes
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N+D=51
D=51-N . Use this to substitute for D below.
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$0.05N+$0.10D=$3.35 . Substitute for D from above.
$0.05N+$0.10(51-N)=$3.35
$0.05N+$5.10-$0.10N=$3.35
-$0.05N=-$1.75
N=35
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ANSWER 1: He has 35 nickels.
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D=51-N=51-36=16
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ANSWER 2: He has 16 nickels.
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CHECK:
$0.05N+$0.10D=$3.35
$0.05(35)+$0.10(16)=$3.35
$1.75+$1.60=$3.35
$3.35=$3.35
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