SOLUTION: Pleas help me with this coin word problem. Tanika has a certain number of nickles and dimes that are worth $4.45. The number of dimes is three less than twice the number of nickles
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Question 1012769: Pleas help me with this coin word problem. Tanika has a certain number of nickles and dimes that are worth $4.45. The number of dimes is three less than twice the number of nickles. How many of each coin does she have?
Found 2 solutions by fractalier, stanbon:
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the number of nickels and dimes, n and d. Then we can write
5n + 10d = 445 (we will work in cents)
Also, we have
d = 2n - 3
Now substitute that into the first equation and get
5n + 10(2n - 3) = 445
5n + 20n - 30 = 445
25n = 475
n = 19 nickels
d = 2(19) - 3 = 35 dimes
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Pleas help me with this coin word problem. Tanika has a certain number of nickles and dimes that are worth $4.45. The number of dimes is three less than twice the number of nickles. How many of each coin does she have?
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Value Equation:: 5n + 10d = 445 cents
Quantity:: d = 2n-3
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Rearrange for elimination:
n + 2d = 89
2n- d = 3
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Modify::
2n + 4d = 178
2n - d = 3
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Subtract and solve for "d"::
5d = 175
d = 35 (# of dimes)
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Solve for "n"::
n = -2d+89
n = -70+89
n = 19 (# of nickels)
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Cheers,
Stan H.
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