Let the number of quarters be x Let the number of dimes be y Value Value Type Number of of of of EACH ALL coin coins coin coins ------------------------------------------- quarters x $0.25 $0.25x dimes y $0.10 $0.10y ------------------------------------------- TOTALS 84 ----- $13.80 The first equation comes from the second column.x + y = 84 The second equation comes from the last column. 0.25x + 0.10y = 13.80 Get rid of decimals by multiplying every term by 100: 25x + 10y = 1380 So we have the system of equations: . We solve by substitution. Solve the first equation for y: x + y = 84 y = 84 - x Substitute (84 - x) for y in 25x + 10y = 1380 25x + 10(84 - x) = 1380 25x + 840 - 10x = 1380 15x + 840 = 1380 15x = 540 x = 36 = the number of quarters. Substitute in y = 84 - x y = 84 - (36 y = 48 dimes. Checking: 36 quarters is $9.00 and 48 dimes is $4.80 That's 84 coins. And indeed $9.00 + $4.80 = $13.80 Edwin