SOLUTION: If a person has dimes and nickles equaling $2.85 and there are 12 more nickles than dimes how many of each coin are there?
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Question 1010463: If a person has dimes and nickles equaling $2.85 and there are 12 more nickles than dimes how many of each coin are there?
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the numbers of nickels and dimes, n and d. Then we have
n = 12 + d
and
5n + 10d = 285 (we work in cents)
we can substitute the first equation into the second and get
5(12 + d) + 10d = 285
60 + 5d + 10d = 285
15d = 225
d = 15 dimes
n = 27 nickels
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