# Questions on Word Problems: Coins answered by real tutors!

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Question 994705: how many 5p coins are in £3.35
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.
Before 1971:
.
((£3.35)(240p/£1))/5p=160.8
ANSWER 1: Before the pound was decimalized (1971),
there were 160.8 five pence coins per pound.
.
Since 1971:
((£3.35)(100p/£1))/5p=67
ANSWER 2: Since the pound was decimalized (1971),
there are 67 five pence coins per pound.

Question 994601: A collection of nickels, dimes, and quarters consist of 10 coins with a total of $1.10. If the number of dimes is equal to the number of nickels, find the number of each type of coins. Please help solve with steps, thanks. :) Found 2 solutions by lwsshak3, macston: Answer by lwsshak3(11500) (Show Source): You can put this solution on YOUR website! A collection of nickels, dimes, and quarters consist of 10 coins with a total of$1.10. If the number of dimes is equal to the number of nickels, find the number of each type of coins. Please help solve with steps, thanks. :)
let x=number of dimes and nickels
10-2x=number of quarters
.05x+.10x+.25(10-2x)=1.10
.05x+.10x+2.5-.5x=1.10
.35x=1.40
x=4
10-2x=10-8=2
number of dimes and nickels=4
10-2x=number of quarters=2

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.
N=number of nickels; D=number of dimes; Q=number of quarters
.
D=N
N+D+Q=10
N+N+Q=10
2N+Q=10
Q=10-2N
.
$0.05N+$0.10D+$0.25Q=$1.10
$0.05N+$0.10N+$0.25Q=$1.10
$0.15N+$0.25Q=$1.10$0.15N+$0.25(10-2N)=$1.10
$0.15N+$2.50-$0.50N=$1.10
-$0.35N=-$1.40
N=4
ANSWER 1: There are 4 nickels.
.
D=N+4
ANSWER 2: There are 4 dimes.
.
Q=10-2N=10-2(4)=10-8=2
ANSWER 3: There are 2 quarters.
.
CHECK:
$0.05N+$0.10D+$0.25Q=$1.10
$0.05(4)+$0.10(4)+$0.25(2)=$1.10
$0.20+$0.40+$0.50=$1.10
$1.10=$1.10

Question 994390: Joe Bob was amazed when he opened the drawer because it contained 173 coins whose value was $11.25. If all coins were either nickels or quarters, how many of each were in the drawer? Answer by stanbon(69061) (Show Source): You can put this solution on YOUR website! Joe Bob was amazed when he opened the drawer because it contained 173 coins whose value was$11.25. If all coins were either nickels or quarters, how many of each were in the drawer?
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Quantity:: n + q = 173 coins
Value:: 5n+25q = 1125 cents
----------------------------
Modify for elimination::
n + q = 173
n + 5q = 225
-----
Subtract and solve for "q":
4q = 52
q = 13 (# of quarters)
------
n = 173 -13 = 160 (# of nickels)
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Cheers,
Stan H.
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Question 994275: in need of help with word problems! help I'm stuck.
22 total coins consisting of quarters & dimes equilling $3.70. how many of each coin does he have Answer by josgarithmetic(13975) (Show Source): You can put this solution on YOUR website! q quarters d dimes Question 994078: Erasers cost 45 cents apiece. Notebooks cost 90 cents apiece. Karla spent$18 for a total of 28 erasers and notebooks. How many notebooks did she buy
You can put this solution on YOUR website!

Let represent the number of notebooks and represent the number of erasers. Then

and

Solve the 2X2 system.

John

My calculator said it, I believe it, that settles it

Question 994077: A cashier has 25 coins consisting of nickels, dimes, and quarters with a value of $4.90. If the number of dimes is one less than twice the number of nickels, how many of each type of coins does she have? Answer by stanbon(69061) (Show Source): You can put this solution on YOUR website! A cashier has 25 coins consisting of nickels, dimes, and quarters with a value of$4.90. If the number of dimes is one less than twice the number of nickels, how many of each type of coins does she have?
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Quantity:: n + d + q = 25 coins
Value::: 5n + 10d+ 25q = 490 cents
Quantity:: d = 2n-1
------------------------------
Rearrange and modify::
n + d + q = 25
n + 2d + 5q = 98
2n - d + 0q = 1
------------
Use some method to solve for n, d, and q
---
I get:
n = 3
d = 5
q = 17
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Cheers,
Stan H.
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Question 994030: I have $14.80 in dimes and quarters the number of quarters is 2 less than 3tims the number of dimes. How many quarters total? Answer by Alex2dadeath(5) (Show Source): You can put this solution on YOUR website! Dimes will be x. A dime is worth 10 cents. So we will start off with .10x (the value of the dime and the x since we are looking for the number of dimes. Now it says there are 2 less than 3 times the number of dimes. Now as you see, that will be marked 3x (3 times the number) and 2 less which will be minus 2 (-2) so you will have 3x-2. A quarter is worth 25 cents so now we have to set up an equation also counting the values of the coins into it so you will now have: .10x + .25(3x-2) = 14.80. Start off by plugging in 25 inside parenthesis which you will then get: .10x + .75x - .50 =$14.80.
Now add .50 to both sides of the equation and also combine like terms (the x's add together) and now you will have: .85x = 15.30. Now this seems off since we are working with cents so you have .85 originally and 15.30. Let's move the decimal to the right on each side twice to the right to leave you with whole numbers to make it easier. So you now have: 85x = 1530. Divide both sides by 85 to leave x alone. x=18.
Now we put x into the top. 10x is 10(18) equals 18 dimes. And as for quarters, you got 3x minus 2 so now replace 18 for the x: 3(18)-2. 18x3= 54-2= 52 quarters.
Now double check your answer to make sure it adds up to the value. .10(dime amount) times the number of dimes (18) equals 1.80. subtract 1.80 from 14.18. You got $13 in quarters. Sum up the amount of quarters$13 dollars in quarters is 52.

-ANSWER: 52 QUARTERS AND 18 DIMES-

Question 994040: Jessica has three times as many nickels as dimes. If the total value of her coins was $1, how many of each kind of coin did she have? Answer by Boreal(1464) (Show Source): You can put this solution on YOUR website! dimes=x nickels=3x .10x+0.05(3x)=1.00 .10x +0.15x=1.00 0.25x=1.00 x=4 3x=12 4 dimes is 40 cents 12 nickels is 60 cents That is a dollar. Question 994032: I have$14.80 in dimes and quarters number of quarters 2 less than 3 times of dimes.
How many quarters in total?

You can put this solution on YOUR website!
Let the number of quarters be Q and the number of dimes be D

That means we have

Question 993963: how much money in quarters does a half gallon container hold
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I do not know.
=============
Why is a duck so much alike?

Question 993296: Alice is 14 years younger than Bob. If Alice's and Bob's Age were added together the result is 96. How old is Alice?
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Hi there,
Alice is 14 years younger than Bob.
A = B - 14
If Alice's and Bob's Age were added
together the result is 96.
A + B = 96
Replace A with B - 14 from top equation.
B - 14 + B = 96
Collect like terms.
B + B = 96 + 14
2B = 110
B = 55
Bob is 55 years old
Alice is 41 years old.
Hope this helps :-)

Question 993375: You have 12 coins in quarters and dimes. If your coins total $1.95, how many of each do you have? Answer by Alan3354(47455) (Show Source): You can put this solution on YOUR website! You have 12 coins in quarters and dimes. If your coins total$1.95, how many of each do you have?
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q + d = 12
25q + 10d = 195

Question 993360: The customer purchases $4.50 in gasoline 3 packs of cigarettes at$1.19 a pack and a quart of $1.25 motor oil.He hands you a dime and a ten dollar bill.what is his correct change Answer by Alan3354(47455) (Show Source): You can put this solution on YOUR website! Add the charges. Subtract the total from$10.10
---------------
You have to know how to do that to survive.

Question 993202: Write the following comparison as a ratio reduced to lowest terms.
42 nickels to 8 dimes

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Write the following comparison as a ratio reduced to lowest terms.
42 nickels to 8 dimes
--------
42:8 = 21:4
-----
Cheers,
Stan H.
-------

Question 992964: Diane coin bank contains 500 nickels and dimes the total value of the coins is $40 how many dimes does she have Answer by lwsshak3(11500) (Show Source): You can put this solution on YOUR website! Diane coin bank contains 500 nickels and dimes the total value of the coins is$40 how many dimes does she have
let x=number of dimes in the bank
500-x=number of nickels in the bank
.10x+.05(500-x=40.00
)=.10x+25-.05x=40.00
.05x=15.00
x=300
number of dimes in the bank=300

Question 992862: Carrie has 40 more nickels that Joan has dimes. They both have the same amount of money. How many coins does each girl have?
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.
J=number of Joan's coins; C=number of Carrie's coins=J+40
$0.10J=$0.05C
$0.10J=$0.05(J+40)
$0.10J=$0.05J+$2.00$0.05J=$2.00 J=40 ANSWER 1: Joan has 40 dimes. . C=J+40=40+40=80 ANSWER 2: Carrie has 80 nickels. . CHECK:$0.10J=$0.05C$0.10(40)=$0.05(80)$4.00=$4.00 Question 992902: Answer by macston(4006) (Show Source): Question 992882: Nina has a penny collection.She has 6,000 pennies.Brad has the same number of pennies.Which could be the number of pennies brad has? Answer by stanbon(69061) (Show Source): You can put this solution on YOUR website! Nina has a penny collection. She has 6,000 pennies. Brad has the same number of pennies. Which could be the number of pennies brad has? ---- Ans: 6000 ------------- Cheers, Stan H. ------------ Question 992712: Using 6 coins, Susan paid 38 cents for a balloon. What 6 cents did she use? Answer by Theo(5548) (Show Source): You can put this solution on YOUR website! looks like a quarter, 2 nickels, and 3 pennies. add them up and you get 38 cents. Question 992760: Frank had a bagful of coins totaling$13.00. He said, "Guess how many of each coin type I have if six less quarters than dimes and ten more than seven times as many nickles than dimes?" (Solve with only using one variable)
When I did the problem I got frank has 14 quarters, 20 nickles, and 150 dimes, which I don't think is right. Please help.

Answer by Edwin McCravy(13211)   (Show Source):
You can put this solution on YOUR website!
Let D = the number of dimes. Then
The value of the dimes = 0.10D


I have...six less quarters than dimes
The number of the quarters = D-6
Value of quarters = 0.25(D-6)


and ten more than seven times as many nickles than dimes
number of nickels = 7D+10
Value of nickels = 0.05(7D+10)

coins totaling $13.00 Value of dimes + Value of quarters + value of nickels = 13.00 D + 0.25(D-6) + 0.05(7D+10) = 13.00 Multiply through by 100 to clear decimals: 100D + 25(D-6) + 5(7D+10) = 1300 100D + 25D - 150 + 37D + 50 = 1300 That works out to 8 3/4 dimes, so something is wrong Edwin Question 992579: Elizabeth had 3 times the number of quarters (25 cents) in her bag than dimes (10 cents). a. If she had a total of 72 coins, how many of them were quarters? b. What was the total dollar value of these coins? Answer by macston(4006) (Show Source): You can put this solution on YOUR website! . D=number of dimes; Q=number of quarters=3D; T=total value . D+Q=72 D+3D=72 4D=72 D=18 There were 18 dimes Q=3D=3(18)=54 ANSWER (a): There were 54 quarters. . T=$0.10(D)+$0.25(Q) T=$0.10(18)+$0.25(54) T=$1.80+$13.50 T=$15.30
ANSWER (b): The value of the coins was $15.30 Question 992580: I have been trying to solve this problem for the last hour, but whatever I try I cannot find the answer. The question is Eddie has$0.95 in dimes and nickles. The total number of coins is one more than twice the number of dimes. How many coins of each type are there? (Solve only using one variable)
I tried
Let dimes=0.95-0.10d
Let nickles= 0.05d
Let number of coins= 2d+1
And the equation 2d+1=0.95-0.1+0.05d
That did not find the right answer, and I have no idea what to do now.

You can put this solution on YOUR website!
.
D=number of dimes; Total coins=2D+1; Number of nickels=2D+1-D=D+1
.
$0.05(D+1)+$0.10D=$0.95$0.05D+$0.05+$0.10D=$0.95$0.15D=$0.90 D=6 ANSWER 1: There are 6 dimes. Number of nickels=D+1=6+1=7 ANSWER 2: There are 7 nickels. . Question 992534: Suppose a spacecraft recently started on a journey inside the solar system. The trip is 2.5 x 10^9 miles long and will take 7 1/2 years. How many miles will the spacecraft travel per year? Answer by stanbon(69061) (Show Source): You can put this solution on YOUR website! Suppose a spacecraft recently started on a journey inside the solar system. The trip is 2.5 x 10^9 miles long and will take 7 1/2 years. How many miles will the spacecraft travel per year? ----- (2.5E9)/7.5 = 333333333.3 miles ---------- Cheers, Stan H. Question 992533: Five less than twice a number is the same as seven times the number. Find he number. Answer by macston(4006) (Show Source): You can put this solution on YOUR website! . x=the number . 2x-5=7x -5=5x -1=x . ANSWER: the number is -1. . CHECK: 2(-1)-5=7(-1) -2-5=-7 -7=-7 Question 992525: A newspaper carrier has$3.90 in change. He has three more quarters than dimes but five times as many nickels as quarters. How many coins of each type doe he have?
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A newspaper carrier has $3.90 in change. He has three more quarters than dimes but five times as many nickels as quarters. How many coins of each type does he have? ----------- 5n + 10d + 25q = 390 cents q = d + 3 n = 5q ------ Substitue for d and n and solve for "q":: 5(5q) + 10(q-3) + 25q = 390 25q + 10q - 30 + 25q = 390 ------ 60q = 420 --- q = 7 (# of quarters) d = q-3 = 4 (# of dimes) n = 5q = 35 (# of nickels) ------------- Cheers, Stan H. ------------ Question 992369: Mary has$6.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and ninety-eight more nickels than dimes, how many coins of each type does she have?
You can put this solution on YOUR website!

Let represent the number of quarters. Then is the number of dimes and is the number of nickels. Nickels are worth 5 cents, dimes are worth 10 cents, and quarters are worth 25 cents. The total value of the coins is $6.00 which is equivalent to 600 cents. Hence: Solve for , then calculate , and John My calculator said it, I believe it, that settles it Question 992200: Ron has 11 coins with a total value of$1.55. The coins are nickels and quarters. How many of each coin does he have?
Answer by Edwin McCravy(13211)   (Show Source):
You can put this solution on YOUR website!
You can either do it with 1 unknown or with 2 unknowns.
I'll do it both ways.

With 1 unknown

Let the number of nickels be x
Then the number of quarters, using
ONE PART = TOTAL MINUS OTHER PART,
is 11-x.
Value      Value
Type       Number       of         of
of          of        EACH       ALL
coin        coins      coin      coins
-------------------------------------------
nickels      x        $0.05$0.05x
quarters   11-x       $0.25$0.25(11-x)
-------------------------------------------
TOTALS      11        -----    $1.55 The equation comes from the column on the right 0.05x + 0.25(11-x) = 1.55 Get rid of decimals by multiplying every term by 100: 5x + 25(11-x) = 155 5x + 275 - 25x = 155 -20x + 275 = 155 -20x = -120 x = 6 = the number of nickels. The number of quarters is 11-x or 11-6 or 5 quarters. Checking: 6 nickels is$0.30 and 5 quarters is $1.25 That's 11 coins. And indeed$0.30 + $1.25 =$1.55

---------------------
With two unknowns

Let the number of nickels be x
Let the number of quarters be y

Value      Value
Type       Number       of         of
of          of        EACH       ALL
coin        coins      coin      coins
-------------------------------------------
nickels       x      $0.05$0.05x
quarters      y      $0.25$0.25y
-------------------------------------------
TOTALS       11      -----     $1.55 The first equation comes from the second column. x + y = 11 The second equation comes from the last column. 0.05x + 0.25y = 1.55 Get rid of decimals by multiplying every term by 100: 5x + 25y = 155 So we have the system of equations: . We solve by substitution. Solve the first equation for y: x + y = 11 y = 11 - x Substitute (11 - x) for y in 5x + 25y = 155 5x + 25(11 - x) = 155 5x + 275 - 25x = 155 -20x + 275 = 155 -20x = -120 x = 6 = the number of nickels. Substitute in y = 11 - x y = 11 - (6 y = 5 quarters. The number of quarters is 11-x or 11-6 or 5 quarters. Checking: 6 nickels is$0.30 and 5 quarters is $1.25 That's 11 coins. And indeed$0.30 + $1.25 =$1.55dwin

Edwin

Question 992104: one and a half candies for one and a half cents how many can you buy with 10cents
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If you can buy one and a half candies for one and a half cents, then you can buy one candy for one cent. I'll leave it to you to figure out the rest of this.

John

My calculator said it, I believe it, that settles it

Question 992103: I'm stuck on this one, 3 more dimes than Nickles twice as many quarters as dimes? Thank you much I appreciate it your help.

You can put this solution on YOUR website!

"3 more dimes than Nickles[sic] twice as many quarters as dimes" is not a question. It is a statement. What is your question?

John

My calculator said it, I believe it, that settles it

Question 992026: What does 4 quarters,13 dimes,8 nickels,19 pennies equals

Question 991988: Clyde and Leah want to combine their money. They have no paper, pencils, or calculators, so they solve the problem mentally by rounding. Clyde has $2.68 and Leah has$3.49. Clyde rounds both amounts to the nearest dollar and then adds them. Leah rounds the amounts to the nearest ten cents and adds them. Which rounding attempt most accurately describes their combined total?
You can put this solution on YOUR website!

First thing to do is to answer this: What is your intuitive sense of what the answer should be?

Step 1: Round 2.68 to the nearest whole number. Round 3.49 to the nearest whole number. Add the two whole numbers.

Step 2: Round 2.68 to the nearest tenth. Round 3.49 to the nearest tenth. Add these two numbers.

Step 3: Add 2.68 to 3.49. Which answer from the first two steps above is closer to the sum of the actual numbers?

John

My calculator said it, I believe it, that settles it

Question 991810: There are 4 more nickels than dimes. The value of the coins is $2.60. Find the number of nickels. Answer by Alan3354(47455) (Show Source): You can put this solution on YOUR website! There are 4 more nickels than dimes. The value of the coins is$2.60. Find the number of nickels.
==============
Without the "4 more", there are pairs worth 15 cents each and a total of $2.40 240/15 = 16 pairs --> 20 nickels Question 991543: suppose your pocket contains 6 quarters, 4 dimes,7 nickels, and 8 pennies, what is the probability that you will not choose 3 dimes if you take charge 3 pieces at a time Answer by Fombitz(25151) (Show Source): You can put this solution on YOUR website! Let's work it backwards. Let's find the probability you will choose 3 dimes. So the complement is the probability we're looking for, Question 991512: The ratio of cents in a quarter to cents in a dollar Answer by Fombitz(25151) (Show Source): You can put this solution on YOUR website! 25 cents in a quarter. 100 cents in a dollar. Question 991535: Ron has 20 coins with a total value of$1.50. The coins are nickels and dimes. How many of each coin does he have?
You can put this solution on YOUR website!
.
N=number of nickels; D=number of dimes
.
N+D=20
N=20-D
.
$0.05N+$0.10D=$1.50$0.05(20-D)+$0.10D=$1.50
$1.00-$0.05D+$0.10D=$1.50
$0.05D=$0.50
D=10
.
N=20-D=20-10=10
ANSWER: He has 10 of each coin.
.
CHECK:
$0.05N+$0.10D=$1.50$0.05(10)+$0.10(10)=$1.50
$0.50+$1.00=$1.50$1.50=$1.50 Question 991400: Cory has 30 coins (all nickels and dimes). He has five times as many nickels as dimes. How much money does he have? Answer by Alan3354(47455) (Show Source): You can put this solution on YOUR website! 30/(5 + 1) = 5 sets of coins --> 25 nickels & 5 dimes. =$1.75
================
He must be very proud.

Question 991135: I have 63 total coins. I have 3x more dimes than quarters and 6 fewer nickels than quarters. How do I write this as a math problem
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Let N, D, and Q stand for the number of nickels, dimes, and quarters you have.
Total number of coins:

3x more dimes than quarters:

6 fewer nickels than quarters:

Question 991178: Show $1.00 three ways by using Q ,D and N Answer by Fombitz(25151) (Show Source): You can put this solution on YOUR website! 4 Q, 0 D, 0 N 0 Q, 10 D, 0 N 0 Q, 0 D, 20 N Question 991258: if you have 35 coins, pennies, dimes and quarters, how many of each to total$3.68
You have the same number of pennies and dimes.

You can put this solution on YOUR website!

is the number of pennies and also the number of dimes. is the number of quarters. The total number of coins is 35, so:

Pennies are worth 1 cent, dimes are worth 10 cents and quarters are worth 25 cents. The total amount of money is 368 cents, so:

Solve the 2X2 system for to find the number of pennies and the number of dimes, and to find the number of quarters.

John

My calculator said it, I believe it, that settles it

Question 991024: Each coin in the collection of 56 coins is neither silver or gold. The number of silver coins is 8 more than 3 times the number of gold coins. Find the number of gold coins.
You can put this solution on YOUR website!
The number of gold coins plus silver coins equals 56.
Let's call the number of gold coins x.
Since the number of silver is 8 more than 3 times the number of gold, we could write it as 8+3X or 3x+8.
Putting these ways of representing gold and silver coins into the first equation gives:
gold + silver =56
x + (3x+8) = 56
x +3x +8 =56
4x +8 = 56
4x+8-8=56-8
4x+0=48
4x=48
4x/4=48/4
x=12
So the number of gold coins is 12.
Silver must be 3(12)+8 = 36+8 = 44.
Plug these number in to check your work.
gold+silver=56
12+44 does equal 56.

Question 990867: sue has $1.95 in dimes and nickels. If she has 9 more dimes as nickels, how many of each coins does she have? Answer by Alan3354(47455) (Show Source): You can put this solution on YOUR website! sue has$1.95 in dimes and nickels. If she has 9 more dimes as nickels, how many of each coins does she have?
========================
Put the "9 more dimes" aside --> pairs of dimes and nickels worth $1.05. They're 15 cents each 105/15 = 7 pairs --> 7 nickels & 16 dimes ============================ The hard way: d = n + 9 10d + 5n = 195 Solve for d and n Question 990857: Tim had a huge jar containing 1040 penny coins.How much does he have in pounds ? If the jar contained 1040 2p coins.How much would he have. Answer by macston(4006) (Show Source): You can put this solution on YOUR website! . (1040p)(£1/100p)=£10.40 . (1040coins)(2p/coin)((£1/100p)=£20.80 Question 990746: Mary has$6.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and eighty-seven more nickels than dimes, how many coins of each type does she have?
You can put this solution on YOUR website!
Let = number of nickels
Let = number of dimes
Let = number of quarters
----------------------------
(1) ( in cents )
(2)
(3)
------------------
There are 3 equations and 3 unknowns, so it's solvable
(2)
Substitute (2) and (3) into (1)
(1)
(1)
Multiply both sids by
(1)
(1)
(1)
and
(2)
(2)
(2)
and
(3)
(3)
(3)
There are 93 nickels
There are 6 dimes
There are 3 quarters
-------------------
Check:
(1)
(1)
(1)
(1)
OK